32=-5(y+4)+3(y+2)

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Solution for 32=-5(y+4)+3(y+2) equation: 



32=-5(y+4)+3(y+2)

We move all terms to the left:

32-(-5(y+4)+3(y+2))=0



We calculate terms in parentheses: -(-5(y+4)+3(y+2)), so:

-5(y+4)+3(y+2)

We multiply parentheses

-5y+3y-20+6

We add all the numbers together, and all the variables

-2y-14

Back to the equation:

-(-2y-14)



We get rid of parentheses

2y+14+32=0

We add all the numbers together, and all the variables

2y+46=0

We move all terms containing y to the left, all other terms to the right

2y=-46

y=-46/2

y=-23

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