32=-6y+4(y+)

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Solution for 32=-6y+4(y+) equation: 



32=-6y+4(y+)

We move all terms to the left:

32-(-6y+4(y+))=0

We add all the numbers together, and all the variables

-(-6y+4(+y))+32=0



We calculate terms in parentheses: -(-6y+4(+y)), so:

-6y+4(+y)

We multiply parentheses

-6y+4y

We add all the numbers together, and all the variables

-2y

Back to the equation:

-(-2y)



We get rid of parentheses

2y+32=0

We move all terms containing y to the left, all other terms to the right

2y=-32

y=-32/2

y=-16

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