32=-6y+4(y+3)

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Solution for 32=-6y+4(y+3) equation: 



32=-6y+4(y+3)

We move all terms to the left:

32-(-6y+4(y+3))=0



We calculate terms in parentheses: -(-6y+4(y+3)), so:

-6y+4(y+3)

We multiply parentheses

-6y+4y+12

We add all the numbers together, and all the variables

-2y+12

Back to the equation:

-(-2y+12)



We get rid of parentheses

2y-12+32=0

We add all the numbers together, and all the variables

2y+20=0

We move all terms containing y to the left, all other terms to the right

2y=-20

y=-20/2

y=-10

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