32=12+5/6b

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Solution for 32=12+5/6b equation: 



32=12+5/6b

We move all terms to the left:

32-(12+5/6b)=0



Domain of the equation: 6b)!=0

b!=0/1

b!=0

b∈R



We add all the numbers together, and all the variables

-(5/6b+12)+32=0

We get rid of parentheses

-5/6b-12+32=0

We multiply all the terms by the denominator


-12*6b+32*6b-5=0

Wy multiply elements

-72b+192b-5=0

We add all the numbers together, and all the variables

120b-5=0

We move all terms containing b to the left, all other terms to the right

120b=5

b=5/120

b=1/24

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