32=12-4(z-1)

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Solution for 32=12-4(z-1) equation: 



32=12-4(z-1)

We move all terms to the left:

32-(12-4(z-1))=0



We calculate terms in parentheses: -(12-4(z-1)), so:

12-4(z-1)

determiningTheFunctionDomain
-4(z-1)+12

We multiply parentheses

-4z+4+12

We add all the numbers together, and all the variables

-4z+16

Back to the equation:

-(-4z+16)



We get rid of parentheses

4z-16+32=0

We add all the numbers together, and all the variables

4z+16=0

We move all terms containing z to the left, all other terms to the right

4z=-16

z=-16/4

z=-4

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