32=2(2n-2)

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Solution for 32=2(2n-2) equation: 



32=2(2n-2)

We move all terms to the left:

32-(2(2n-2))=0



We calculate terms in parentheses: -(2(2n-2)), so:

2(2n-2)

We multiply parentheses

4n-4

Back to the equation:

-(4n-4)



We get rid of parentheses

-4n+4+32=0

We add all the numbers together, and all the variables

-4n+36=0

We move all terms containing n to the left, all other terms to the right

-4n=-36

n=-36/-4

n=+9

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