32=2(3f-2)

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Solution for 32=2(3f-2) equation: 



32=2(3f-2)

We move all terms to the left:

32-(2(3f-2))=0



We calculate terms in parentheses: -(2(3f-2)), so:

2(3f-2)

We multiply parentheses

6f-4

Back to the equation:

-(6f-4)



We get rid of parentheses

-6f+4+32=0

We add all the numbers together, and all the variables

-6f+36=0

We move all terms containing f to the left, all other terms to the right

-6f=-36

f=-36/-6

f=+6

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