32=2(6-k)

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Solution for 32=2(6-k) equation: 



32=2(6-k)

We move all terms to the left:

32-(2(6-k))=0

We add all the numbers together, and all the variables

-(2(-1k+6))+32=0



We calculate terms in parentheses: -(2(-1k+6)), so:

2(-1k+6)

We multiply parentheses

-2k+12

Back to the equation:

-(-2k+12)



We get rid of parentheses

2k-12+32=0

We add all the numbers together, and all the variables

2k+20=0

We move all terms containing k to the left, all other terms to the right

2k=-20

k=-20/2

k=-10

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