32=2(j+10)

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Solution for 32=2(j+10) equation: 



32=2(j+10)

We move all terms to the left:

32-(2(j+10))=0



We calculate terms in parentheses: -(2(j+10)), so:

2(j+10)

We multiply parentheses

2j+20

Back to the equation:

-(2j+20)



We get rid of parentheses

-2j-20+32=0

We add all the numbers together, and all the variables

-2j+12=0

We move all terms containing j to the left, all other terms to the right

-2j=-12

j=-12/-2

j=+6

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