32=2(u-4)+3u

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Solution for 32=2(u-4)+3u equation: 



32=2(u-4)+3u

We move all terms to the left:

32-(2(u-4)+3u)=0



We calculate terms in parentheses: -(2(u-4)+3u), so:

2(u-4)+3u

We add all the numbers together, and all the variables

3u+2(u-4)

We multiply parentheses

3u+2u-8

We add all the numbers together, and all the variables

5u-8

Back to the equation:

-(5u-8)



We get rid of parentheses

-5u+8+32=0

We add all the numbers together, and all the variables

-5u+40=0

We move all terms containing u to the left, all other terms to the right

-5u=-40

u=-40/-5

u=+8

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