32=2(u-4)-6u

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Solution for 32=2(u-4)-6u equation: 



32=2(u-4)-6u

We move all terms to the left:

32-(2(u-4)-6u)=0



We calculate terms in parentheses: -(2(u-4)-6u), so:

2(u-4)-6u

We add all the numbers together, and all the variables

-6u+2(u-4)

We multiply parentheses

-6u+2u-8

We add all the numbers together, and all the variables

-4u-8

Back to the equation:

-(-4u-8)



We get rid of parentheses

4u+8+32=0

We add all the numbers together, and all the variables

4u+40=0

We move all terms containing u to the left, all other terms to the right

4u=-40

u=-40/4

u=-10

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