32=2(v-4)+6v

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Solution for 32=2(v-4)+6v equation: 



32=2(v-4)+6v

We move all terms to the left:

32-(2(v-4)+6v)=0



We calculate terms in parentheses: -(2(v-4)+6v), so:

2(v-4)+6v

We add all the numbers together, and all the variables

6v+2(v-4)

We multiply parentheses

6v+2v-8

We add all the numbers together, and all the variables

8v-8

Back to the equation:

-(8v-8)



We get rid of parentheses

-8v+8+32=0

We add all the numbers together, and all the variables

-8v+40=0

We move all terms containing v to the left, all other terms to the right

-8v=-40

v=-40/-8

v=+5

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