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32=25x^2-4
We move all terms to the left:
32-(25x^2-4)=0
We get rid of parentheses
-25x^2+4+32=0
We add all the numbers together, and all the variables
-25x^2+36=0
a = -25; b = 0; c = +36;
Δ = b2-4ac
Δ = 02-4·(-25)·36
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3600}=60$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-60}{2*-25}=\frac{-60}{-50} =1+1/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+60}{2*-25}=\frac{60}{-50} =-1+1/5 $
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