32=2E-15x2-0.5x+36

Solution for 32=2E-15x2-0.5x+36 equation:

32=2-15E^2-0.5E+36

We move all terms to the left:

32-(2-15E^2-0.5E+36)=0

We get rid of parentheses

15E^2+0.5E-2-36+32=0

We add all the numbers together, and all the variables

15E^2+0.5E-6=0

a = 15; b = 0.5; c = -6;
Δ = b2-4ac
Δ = 0.52-4·15·(-6)
Δ = 360.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$E_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$E_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$E_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.5)-\sqrt{360.25}}{2*15}=\frac{-0.5-\sqrt{360.25}}{30}
$
$E_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.5)+\sqrt{360.25}}{2*15}=\frac{-0.5+\sqrt{360.25}}{30}
$