32=2v+4(v+5)

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Solution for 32=2v+4(v+5) equation: 



32=2v+4(v+5)

We move all terms to the left:

32-(2v+4(v+5))=0



We calculate terms in parentheses: -(2v+4(v+5)), so:

2v+4(v+5)

We multiply parentheses

2v+4v+20

We add all the numbers together, and all the variables

6v+20

Back to the equation:

-(6v+20)



We get rid of parentheses

-6v-20+32=0

We add all the numbers together, and all the variables

-6v+12=0

We move all terms containing v to the left, all other terms to the right

-6v=-12

v=-12/-6

v=+2

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