32=2x+2(3x-4)

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Solution for 32=2x+2(3x-4) equation: 



32=2x+2(3x-4)

We move all terms to the left:

32-(2x+2(3x-4))=0



We calculate terms in parentheses: -(2x+2(3x-4)), so:

2x+2(3x-4)

We multiply parentheses

2x+6x-8

We add all the numbers together, and all the variables

8x-8

Back to the equation:

-(8x-8)



We get rid of parentheses

-8x+8+32=0

We add all the numbers together, and all the variables

-8x+40=0

We move all terms containing x to the left, all other terms to the right

-8x=-40

x=-40/-8

x=+5

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