32=3(y+4)-7

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Solution for 32=3(y+4)-7 equation: 



32=3(y+4)-7

We move all terms to the left:

32-(3(y+4)-7)=0



We calculate terms in parentheses: -(3(y+4)-7), so:

3(y+4)-7

We multiply parentheses

3y+12-7

We add all the numbers together, and all the variables

3y+5

Back to the equation:

-(3y+5)



We get rid of parentheses

-3y-5+32=0

We add all the numbers together, and all the variables

-3y+27=0

We move all terms containing y to the left, all other terms to the right

-3y=-27

y=-27/-3

y=+9

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