32=3(y+4)-7y

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Solution for 32=3(y+4)-7y equation: 



32=3(y+4)-7y

We move all terms to the left:

32-(3(y+4)-7y)=0



We calculate terms in parentheses: -(3(y+4)-7y), so:

3(y+4)-7y

We add all the numbers together, and all the variables

-7y+3(y+4)

We multiply parentheses

-7y+3y+12

We add all the numbers together, and all the variables

-4y+12

Back to the equation:

-(-4y+12)



We get rid of parentheses

4y-12+32=0

We add all the numbers together, and all the variables

4y+20=0

We move all terms containing y to the left, all other terms to the right

4y=-20

y=-20/4

y=-5

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