32=3+2n-3(4n-2)

Solution for 32=3+2n-3(4n-2) equation:

32=3+2n-3(4n-2)

We move all terms to the left:

32-(3+2n-3(4n-2))=0


We calculate terms in parentheses: -(3+2n-3(4n-2)), so:

3+2n-3(4n-2)

determiningTheFunctionDomain
2n-3(4n-2)+3

We multiply parentheses

2n-12n+6+3

We add all the numbers together, and all the variables

-10n+9

Back to the equation:

-(-10n+9)


We get rid of parentheses

10n-9+32=0

We add all the numbers together, and all the variables

10n+23=0

We move all terms containing n to the left, all other terms to the right

10n=-23

n=-23/10

n=-2+3/10