32=4(7y-2)

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Solution for 32=4(7y-2) equation: 



32=4(7y-2)

We move all terms to the left:

32-(4(7y-2))=0



We calculate terms in parentheses: -(4(7y-2)), so:

4(7y-2)

We multiply parentheses

28y-8

Back to the equation:

-(28y-8)



We get rid of parentheses

-28y+8+32=0

We add all the numbers together, and all the variables

-28y+40=0

We move all terms containing y to the left, all other terms to the right

-28y=-40

y=-40/-28

y=1+3/7

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