32=4(y+2)+2y

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Solution for 32=4(y+2)+2y equation: 



32=4(y+2)+2y

We move all terms to the left:

32-(4(y+2)+2y)=0



We calculate terms in parentheses: -(4(y+2)+2y), so:

4(y+2)+2y

We add all the numbers together, and all the variables

2y+4(y+2)

We multiply parentheses

2y+4y+8

We add all the numbers together, and all the variables

6y+8

Back to the equation:

-(6y+8)



We get rid of parentheses

-6y-8+32=0

We add all the numbers together, and all the variables

-6y+24=0

We move all terms containing y to the left, all other terms to the right

-6y=-24

y=-24/-6

y=+4

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