32=4(y+2)-8y

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Solution for 32=4(y+2)-8y equation: 



32=4(y+2)-8y

We move all terms to the left:

32-(4(y+2)-8y)=0



We calculate terms in parentheses: -(4(y+2)-8y), so:

4(y+2)-8y

We add all the numbers together, and all the variables

-8y+4(y+2)

We multiply parentheses

-8y+4y+8

We add all the numbers together, and all the variables

-4y+8

Back to the equation:

-(-4y+8)



We get rid of parentheses

4y-8+32=0

We add all the numbers together, and all the variables

4y+24=0

We move all terms containing y to the left, all other terms to the right

4y=-24

y=-24/4

y=-6

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