32=4(y+3)

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Solution for 32=4(y+3) equation: 



32=4(y+3)

We move all terms to the left:

32-(4(y+3))=0



We calculate terms in parentheses: -(4(y+3)), so:

4(y+3)

We multiply parentheses

4y+12

Back to the equation:

-(4y+12)



We get rid of parentheses

-4y-12+32=0

We add all the numbers together, and all the variables

-4y+20=0

We move all terms containing y to the left, all other terms to the right

-4y=-20

y=-20/-4

y=+5

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