32=4(y+5)-7y

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Solution for 32=4(y+5)-7y equation: 



32=4(y+5)-7y

We move all terms to the left:

32-(4(y+5)-7y)=0



We calculate terms in parentheses: -(4(y+5)-7y), so:

4(y+5)-7y

We add all the numbers together, and all the variables

-7y+4(y+5)

We multiply parentheses

-7y+4y+20

We add all the numbers together, and all the variables

-3y+20

Back to the equation:

-(-3y+20)



We get rid of parentheses

3y-20+32=0

We add all the numbers together, and all the variables

3y+12=0

We move all terms containing y to the left, all other terms to the right

3y=-12

y=-12/3

y=-4

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