32=4(y-2)+4y

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Solution for 32=4(y-2)+4y equation: 



32=4(y-2)+4y

We move all terms to the left:

32-(4(y-2)+4y)=0



We calculate terms in parentheses: -(4(y-2)+4y), so:

4(y-2)+4y

We add all the numbers together, and all the variables

4y+4(y-2)

We multiply parentheses

4y+4y-8

We add all the numbers together, and all the variables

8y-8

Back to the equation:

-(8y-8)



We get rid of parentheses

-8y+8+32=0

We add all the numbers together, and all the variables

-8y+40=0

We move all terms containing y to the left, all other terms to the right

-8y=-40

y=-40/-8

y=+5

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