32=6(u+3)-4u

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Solution for 32=6(u+3)-4u equation: 



32=6(u+3)-4u

We move all terms to the left:

32-(6(u+3)-4u)=0



We calculate terms in parentheses: -(6(u+3)-4u), so:

6(u+3)-4u

We add all the numbers together, and all the variables

-4u+6(u+3)

We multiply parentheses

-4u+6u+18

We add all the numbers together, and all the variables

2u+18

Back to the equation:

-(2u+18)



We get rid of parentheses

-2u-18+32=0

We add all the numbers together, and all the variables

-2u+14=0

We move all terms containing u to the left, all other terms to the right

-2u=-14

u=-14/-2

u=+7

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