32=6(v+5)-8v

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Solution for 32=6(v+5)-8v equation: 



32=6(v+5)-8v

We move all terms to the left:

32-(6(v+5)-8v)=0



We calculate terms in parentheses: -(6(v+5)-8v), so:

6(v+5)-8v

We add all the numbers together, and all the variables

-8v+6(v+5)

We multiply parentheses

-8v+6v+30

We add all the numbers together, and all the variables

-2v+30

Back to the equation:

-(-2v+30)



We get rid of parentheses

2v-30+32=0

We add all the numbers together, and all the variables

2v+2=0

We move all terms containing v to the left, all other terms to the right

2v=-2

v=-2/2

v=-1

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