32=7z-z

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Solution for 32=7z-z equation: 



32=7z-z

We move all terms to the left:

32-(7z-z)=0

We add all the numbers together, and all the variables

-(+6z)+32=0

We get rid of parentheses

-6z+32=0

We move all terms containing z to the left, all other terms to the right

-6z=-32

z=-32/-6

z=5+1/3

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