32=k2*2*2

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Solution for 32=k2*2*2 equation:



32=k2*2*2
We move all terms to the left:
32-(k2*2*2)=0
We add all the numbers together, and all the variables
-(+k2*2*2)+32=0
We get rid of parentheses
-k2*2*2+32=0
Wy multiply elements
-4k^2*2+32=0
Wy multiply elements
-8k^2+32=0
a = -8; b = 0; c = +32;
Δ = b2-4ac
Δ = 02-4·(-8)·32
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1024}=32$
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-32}{2*-8}=\frac{-32}{-16} =+2 $
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+32}{2*-8}=\frac{32}{-16} =-2 $

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