32b2=8

Solution for 32b2=8 equation:

32b^2=8

We move all terms to the left:

32b^2-(8)=0

a = 32; b = 0; c = -8;
Δ = b2-4ac
Δ = 02-4·32·(-8)
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1024}=32$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-32}{2*32}=\frac{-32}{64}
=-1/2
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+32}{2*32}=\frac{32}{64}
=1/2
$