32n=4(n-5)

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Solution for 32n=4(n-5) equation: 



32n=4(n-5)

We move all terms to the left:

32n-(4(n-5))=0



We calculate terms in parentheses: -(4(n-5)), so:

4(n-5)

We multiply parentheses

4n-20

Back to the equation:

-(4n-20)



We get rid of parentheses

32n-4n+20=0

We add all the numbers together, and all the variables

28n+20=0

We move all terms containing n to the left, all other terms to the right

28n=-20

n=-20/28

n=-5/7

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