32x(10-8)=6

Solution for 32x(10-8)=6 equation:

32x(10-8)=6

We move all terms to the left:

32x(10-8)-(6)=0

We add all the numbers together, and all the variables

32x2-6=0

We add all the numbers together, and all the variables

32x^2-6=0

a = 32; b = 0; c = -6;
Δ = b2-4ac
Δ = 02-4·32·(-6)
Δ = 768
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{768}=\sqrt{256*3}=\sqrt{256}*\sqrt{3}=16\sqrt{3}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-16\sqrt{3}}{2*32}=\frac{0-16\sqrt{3}}{64}
=-\frac{16\sqrt{3}}{64}
=-\frac{\sqrt{3}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+16\sqrt{3}}{2*32}=\frac{0+16\sqrt{3}}{64}
=\frac{16\sqrt{3}}{64}
=\frac{\sqrt{3}}{4}
$