32x(x-1)=-8(4-x)+24x

Solution for 32x(x-1)=-8(4-x)+24x equation:

32x(x-1)=-8(4-x)+24x

We move all terms to the left:

32x(x-1)-(-8(4-x)+24x)=0

We add all the numbers together, and all the variables

32x(x-1)-(-8(-1x+4)+24x)=0

We multiply parentheses

32x^2-32x-(-8(-1x+4)+24x)=0


We calculate terms in parentheses: -(-8(-1x+4)+24x), so:

-8(-1x+4)+24x

We add all the numbers together, and all the variables

24x-8(-1x+4)

We multiply parentheses

24x+8x-32

We add all the numbers together, and all the variables

32x-32

Back to the equation:

-(32x-32)


We get rid of parentheses

32x^2-32x-32x+32=0

We add all the numbers together, and all the variables

32x^2-64x+32=0

a = 32; b = -64; c = +32;
Δ = b2-4ac
Δ = -642-4·32·32
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{64}{64}=1$