32x+20=7(4x+4)+4x-8

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Solution for 32x+20=7(4x+4)+4x-8 equation: 



32x+20=7(4x+4)+4x-8

We move all terms to the left:

32x+20-(7(4x+4)+4x-8)=0



We calculate terms in parentheses: -(7(4x+4)+4x-8), so:

7(4x+4)+4x-8

We add all the numbers together, and all the variables

4x+7(4x+4)-8

We multiply parentheses

4x+28x+28-8

We add all the numbers together, and all the variables

32x+20

Back to the equation:

-(32x+20)



We get rid of parentheses

32x-32x-20+20=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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