32x+2=2(3x+27)

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Solution for 32x+2=2(3x+27) equation: 



32x+2=2(3x+27)

We move all terms to the left:

32x+2-(2(3x+27))=0



We calculate terms in parentheses: -(2(3x+27)), so:

2(3x+27)

We multiply parentheses

6x+54

Back to the equation:

-(6x+54)



We get rid of parentheses

32x-6x-54+2=0

We add all the numbers together, and all the variables

26x-52=0

We move all terms containing x to the left, all other terms to the right

26x=52

x=52/26

x=2

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