32x+x+3-5=9+32x-(4x-2)

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Solution for 32x+x+3-5=9+32x-(4x-2) equation: 



32x+x+3-5=9+32x-(4x-2)

We move all terms to the left:

32x+x+3-5-(9+32x-(4x-2))=0

We add all the numbers together, and all the variables

33x-(9+32x-(4x-2))-2=0



We calculate terms in parentheses: -(9+32x-(4x-2)), so:

9+32x-(4x-2)

determiningTheFunctionDomain
32x-(4x-2)+9

We get rid of parentheses

32x-4x+2+9

We add all the numbers together, and all the variables

28x+11

Back to the equation:

-(28x+11)



We get rid of parentheses

33x-28x-11-2=0

We add all the numbers together, and all the variables

5x-13=0

We move all terms containing x to the left, all other terms to the right

5x=13

x=13/5

x=2+3/5

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