32x-3=27(x+1)/2

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Solution for 32x-3=27(x+1)/2 equation: 



32x-3=27(x+1)/2

We move all terms to the left:

32x-3-(27(x+1)/2)=0

We multiply all the terms by the denominator


32x*2)-(27(x+1)-3*2)=0

We add all the numbers together, and all the variables

32x*2)-(27(x+1)=0

Wy multiply elements

64x^2=0

a = 64; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·64·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{128}=0$

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