32x-5=2(3x-2)

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Solution for 32x-5=2(3x-2) equation: 



32x-5=2(3x-2)

We move all terms to the left:

32x-5-(2(3x-2))=0



We calculate terms in parentheses: -(2(3x-2)), so:

2(3x-2)

We multiply parentheses

6x-4

Back to the equation:

-(6x-4)



We get rid of parentheses

32x-6x+4-5=0

We add all the numbers together, and all the variables

26x-1=0

We move all terms containing x to the left, all other terms to the right

26x=1

x=1/26

x=1/26

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