32x-7=6(5x-2)+2x+5

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Solution for 32x-7=6(5x-2)+2x+5 equation: 



32x-7=6(5x-2)+2x+5

We move all terms to the left:

32x-7-(6(5x-2)+2x+5)=0



We calculate terms in parentheses: -(6(5x-2)+2x+5), so:

6(5x-2)+2x+5

We add all the numbers together, and all the variables

2x+6(5x-2)+5

We multiply parentheses

2x+30x-12+5

We add all the numbers together, and all the variables

32x-7

Back to the equation:

-(32x-7)



We get rid of parentheses

32x-32x+7-7=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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