32x2+18x-17=0

Solution for 32x2+18x-17=0 equation:

32x^2+18x-17=0

a = 32; b = 18; c = -17;
Δ = b2-4ac
Δ = 182-4·32·(-17)
Δ = 2500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2500}=50$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-50}{2*32}=\frac{-68}{64}
=-1+1/16
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+50}{2*32}=\frac{32}{64}
=1/2
$