32x2+3x-2=27

Solution for 32x2+3x-2=27 equation:

32x^2+3x-2=27

We move all terms to the left:

32x^2+3x-2-(27)=0

We add all the numbers together, and all the variables

32x^2+3x-29=0

a = 32; b = 3; c = -29;
Δ = b2-4ac
Δ = 32-4·32·(-29)
Δ = 3721
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3721}=61$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-61}{2*32}=\frac{-64}{64}
=-1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+61}{2*32}=\frac{58}{64}
=29/32
$