32x=8x2

Solution for 32x=8x2 equation:

32x=8x^2

We move all terms to the left:

32x-(8x^2)=0

determiningTheFunctionDomain
-8x^2+32x=0

a = -8; b = 32; c = 0;
Δ = b2-4ac
Δ = 322-4·(-8)·0
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1024}=32$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(32)-32}{2*-8}=\frac{-64}{-16}
=+4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(32)+32}{2*-8}=\frac{0}{-16}
=0
$