32y-12y=100+20y-y

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Solution for 32y-12y=100+20y-y equation: 



32y-12y=100+20y-y

We move all terms to the left:

32y-12y-(100+20y-y)=0

We add all the numbers together, and all the variables

32y-12y-(19y+100)=0

We add all the numbers together, and all the variables

20y-(19y+100)=0

We get rid of parentheses

20y-19y-100=0

We add all the numbers together, and all the variables

y-100=0

We move all terms containing y to the left, all other terms to the right

y=100

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