32y-16(y+2)=-4(y-2)

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Solution for 32y-16(y+2)=-4(y-2) equation: 



32y-16(y+2)=-4(y-2)

We move all terms to the left:

32y-16(y+2)-(-4(y-2))=0

We multiply parentheses

32y-16y-(-4(y-2))-32=0



We calculate terms in parentheses: -(-4(y-2)), so:

-4(y-2)

We multiply parentheses

-4y+8

Back to the equation:

-(-4y+8)



We add all the numbers together, and all the variables

16y-(-4y+8)-32=0

We get rid of parentheses

16y+4y-8-32=0

We add all the numbers together, and all the variables

20y-40=0

We move all terms containing y to the left, all other terms to the right

20y=40

y=40/20

y=2

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