32y-4(7y+3)=16

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Solution for 32y-4(7y+3)=16 equation:


32y-4(7y+3)=16

We simplify the equation to the form, which is simple to understand 
32y-4(7y+3)=16

Reorder the terms in parentheses
32y+(-28y-12)=16

Remove unnecessary parentheses
+32y-28y-12=+16

We move all terms containing y to the left and all other terms to the right. 
+32y-28y=+16+12

We simplify left and right side of the equation. 
+4y=+28

We divide both sides of the equation by 4 to get y. 
y=7

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