32y2+-24y=0

Solution for 32y2+-24y=0 equation:

32y^2+-24y=0

We add all the numbers together, and all the variables

32y^2-24y=0

a = 32; b = -24; c = 0;
Δ = b2-4ac
Δ = -242-4·32·0
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-24}{2*32}=\frac{0}{64}
=0
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+24}{2*32}=\frac{48}{64}
=3/4
$