33(2a+3)-4(3a-6)=15

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Solution for 33(2a+3)-4(3a-6)=15 equation: 



33(2a+3)-4(3a-6)=15

We move all terms to the left:

33(2a+3)-4(3a-6)-(15)=0

We multiply parentheses

66a-12a+99+24-15=0

We add all the numbers together, and all the variables

54a+108=0

We move all terms containing a to the left, all other terms to the right

54a=-108

a=-108/54

a=-2

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