33(2m+4)=2(3m+6)

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Solution for 33(2m+4)=2(3m+6) equation: 



33(2m+4)=2(3m+6)

We move all terms to the left:

33(2m+4)-(2(3m+6))=0

We multiply parentheses

66m-(2(3m+6))+132=0



We calculate terms in parentheses: -(2(3m+6)), so:

2(3m+6)

We multiply parentheses

6m+12

Back to the equation:

-(6m+12)



We get rid of parentheses

66m-6m-12+132=0

We add all the numbers together, and all the variables

60m+120=0

We move all terms containing m to the left, all other terms to the right

60m=-120

m=-120/60

m=-2

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