33(2x+3)-4x=1-4(x-5)

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Solution for 33(2x+3)-4x=1-4(x-5) equation: 



33(2x+3)-4x=1-4(x-5)

We move all terms to the left:

33(2x+3)-4x-(1-4(x-5))=0

We add all the numbers together, and all the variables

-4x+33(2x+3)-(1-4(x-5))=0

We multiply parentheses

-4x+66x-(1-4(x-5))+99=0



We calculate terms in parentheses: -(1-4(x-5)), so:

1-4(x-5)

determiningTheFunctionDomain
-4(x-5)+1

We multiply parentheses

-4x+20+1

We add all the numbers together, and all the variables

-4x+21

Back to the equation:

-(-4x+21)



We add all the numbers together, and all the variables

62x-(-4x+21)+99=0

We get rid of parentheses

62x+4x-21+99=0

We add all the numbers together, and all the variables

66x+78=0

We move all terms containing x to the left, all other terms to the right

66x=-78

x=-78/66

x=-1+2/11

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