33(3x+3)-3(3x+3)=3

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Solution for 33(3x+3)-3(3x+3)=3 equation:



33(3x+3)-3(3x+3)=3
We move all terms to the left:
33(3x+3)-3(3x+3)-(3)=0
We multiply parentheses
99x-9x+99-9-3=0
We add all the numbers together, and all the variables
90x+87=0
We move all terms containing x to the left, all other terms to the right
90x=-87
x=-87/90
x=-29/30

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