33(3x+3)-3(3x+3)=3

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Solution for 33(3x+3)-3(3x+3)=3 equation: 



33(3x+3)-3(3x+3)=3

We move all terms to the left:

33(3x+3)-3(3x+3)-(3)=0

We multiply parentheses

99x-9x+99-9-3=0

We add all the numbers together, and all the variables

90x+87=0

We move all terms containing x to the left, all other terms to the right

90x=-87

x=-87/90

x=-29/30

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